Note that S stands
for problems from sample final. |
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Week |
Day |
Date |
Section |
Problems |
Due Date |
1 |
Wed |
9/8 |
1.2 |
13, 16, 28 |
9/17 |
1.4 |
4, 5, 10, 19 |
9/17 |
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1 |
Fri |
9/10 |
1.5 |
1, 7, 13, 18, S3b (recall, S3b=problem 3b on sample final) | 9/17 |
2 |
Wed | 9/15 |
1.6 |
10, 12, additional problem
written below |
9/24 |
2 |
Fri | 9/17 |
2.1 |
14, 15, 24, 38, 39 |
9/24 |
3 |
Wed | 9/22 |
2.3 |
6, 12, 14, 19 |
10/1 |
3 |
Fri | 9/24 |
2.3 |
21, 24, 30, 34 |
10/1 |
2.4 |
16, 20a |
10/1 |
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4 |
Wed | 9/29 |
2.5 |
2, 9, 15, 19, S7 |
10/8 |
4 |
Fri | 10/1 |
2.6 |
3, 7, 12, 21,S2, S9a |
10/8 |
5 |
Wed | 10/6 |
5.1 |
4, 10, 13 |
10/15 |
5.2 |
1, 5, 11 |
10/15 |
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5 |
Fri | 10/8 |
5.2 |
12, 15 |
10/15 |
5.3 |
1, 2, 4, 6 |
10/22 |
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6 |
Wed | 10/13 |
3.1 |
4, 10, 18 |
10/22 |
3.2 |
4, 5 |
10/22 |
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6 |
Wed | 10/13 |
First Exam -- 5:00 to 6:00
PM or 6:10 to 7:10 PM. |
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6 |
Fri | 10/15 |
3.3 |
2, 6, 8 |
10/22 |
7 |
Wed | 10/20 |
6.1 |
2, 5, 6, 9, 16, 21 |
10/29 |
7 |
Fri | 10/22 |
6.2 |
3, 4, 8, 10, 17 |
10/29 |
8 |
Wed | 10/27 |
3.4 |
2, 4, 10, 12, 14 |
11/5 |
8 |
Fri | 10/29 |
6.3 |
1, 7, 8, 12, 14, S9b |
11/5 |
9 |
Wed | 11/3 |
5.4 |
2, 7, 8, 12, 17, 20 |
11/12 |
9 |
Fri | 11/5 |
1.7 |
9, 18, 24, 26, 33 |
11/12 |
5.5 |
2, 8, 13, S8 |
11/12 |
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10 |
Wed | 11/10 |
5.5 |
22, 28, 29, S4a |
11/19 |
10 |
Wed | 11/10 |
Second exam -- 5:00 to
6:00 PM or 6:10 to 7:10 PM. |
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10 |
Fri | 11/12 |
5.5 |
(catch up) |
11/19 |
11 |
Wed | 11/17 |
7.1 |
5, 10, 11, 18, 19, 20, S3a |
11/24 |
11 |
Fri | 11/19 |
7.2 |
1, 8, 15, 18, 21, S6 |
12/3 |
12 |
Wed | 11/24 |
7.3 |
1, 3, 4, 11, S5 |
12/3 |
12 |
Fri | 11/26 |
No class |
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13 |
Wed | 12/1 |
7.3 |
6, 7, 12, S4b |
12/10 |
13 |
Fri | 12/3 |
4.1 |
5, 10, 11 |
12/10 |
14 |
Wed | 12/8 |
4.1 |
15, 18, 19 |
12/15 |
14 |
Wed | 12/8 |
Third Exam -- 5:00 to 6:00
PM or 6:10 to 7:10 PM. |
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14 |
Fri | 12/10 |
4.2 |
2, 9, 16, 23, S1 |
12/15 |
15 |
Wed | 12/15 |
Review |
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15 |
Thu |
12/16 |
FINAL EXAM -- 1:30 PM to
4:30 PM |
Additional problem for section 1.6
Let S(x1, x2) = (x1 + x2, 2x2 - x1, x1) and T(x1, x2, x3) = (x2 + x3, x1 + x3, x1 + x2).
S(x1, x2) | = A![]() ![]() ![]() |
|
T(x1, x2, x3) | = B![]() ![]() ![]() |
T(S(x1, x2)) | = C![]() ![]() ![]() |
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