Math 5-335 Fall 2003
Hints for the December 4 and
and December 11 homework
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Hint for exercise #28 in §8.6
By definition, the hyperbolic area (or Poincaré area) of a
region in the upper
half plane is
. This doesn't correspond directly to Euclidean area in
any straightforward way. To have a model of something with physical
connotations, think of a distribution of mass (or static electrical
charge, or whatever) that's proportional to 1/y2,
i.e., inversely proportional to the square of the distance
from the x-axis. So, there's a lot of mass close to the x-axis,
but very little mass per unit area far away from the x-axis.
Generally, integrals like this are done as iterated integrals, with the order of integration depending on the shape of the region. Thus, if the region looks like this:
On the other hand, if the region looks like this:
Finally, of course, if a region is of neither of these types, then we decompose it so that each of the pieces is of one type or the other.
Oh yes, one other comment (slightly vague, but specific examples will be
given in class. It's that some regions that have infinite Euclidean area
will have finite hyperbolic area (as in this problem, actually, as well as
for one type of asymptotic triangle). The opposite situation is
possible too. The second situation is fairly common for regions near
the x-axis -- but asymptotic triangles, where the bottom end
is tightly pinched, are a noteworthy exception.
Hint for exercise #31 in §8.6
First of all, I just want to affirm that the suggestion in the text is not only
a valid method, but also a lot easier than calculating an
integral. Just look for the appropriate formula in the text, where hyperbolic
area is expressed in terms of angular measures.
Another point worth mentioning is that (
Comments and questions top;
roberts@math.umn.edu
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,0) is an asymptotic vertex of this triangle.
We could get a more intuitive picture of this by calling the asymptotic vertex
(0,
). Whether you
call this point by its official name or by some unofficial name as I'm doing
here, the main consequence is that two of the sides of the triangle are
vertical (and infinite at the top end), while the third side is a circular arc.