Math 5-335     Fall 2003
Hints and supplementary exercises for the October 16 homework

Supplementary exercise #1   Consider the same triangle   ABC   as in problem 30 of §2.5.

  1. Draw the triangle, with its sides extended to the lines that contain them, and plot the following points:
    • (-1,2,0) = -A +2B = B - (A - B)
    • (-1,0,2) = -A +2C = C - (A - C). (By Theorem 16 in Chapter 2, these points should be on the lines   and     respectively.
    • Draw the line joining the two points that you plotted in part a.
    • Show that a point (r,s,t)   is on this line if and only if   r = -1.
    • Show, more generally, that the equality   r = a,   where   a   is a real number, characterizes the line that joins the points   (a,-a+1,0)   and   (a,0,-a+1).

Supplementary exercise #2   Consider the same triangle   ABC   as in problem 30 of §2.5.

  1. Sketch the line joining   A to the point   (0,1/3,2/3)   (which lies on the line ).  
  2. Show that for every point   (r,s,t)   of this line, the equality of ratios   s/t = 1/2   holds.
  3. Show that, more generally, if P = (0,b,c)   is a point of the line , then for every point   (r,s,t)   of the line joining A   and   P,   the equality of ratios   s/t = b/c   holds.

    Hint for §2.5, problem 30   In the first part of the problem, we're supposed to plot the line consisting of points whose points have barycentric coordinates   (r,s,t)   where   r   has a constant value.   We can draw such a line by finding two points on it.   The two easiest such points to find are the ones where the line   r = (constant)   intersects the lines   and   .   This was done in Supplementary exercise #1. You don't need to use the formula here; it's good enough just to solve on a case-by-case basis, noting that the lines   and     are characterized by the equations   t = 0   and   s = 0   respectively.   Lines of the form   s = (constant)   and   t = (constant)   are handled similarly.

    Hint for §3.12, problem 64   (Re-written retroactively)   Here's a diagram of the setup:

    According to the plan presented in the text   we're given that   D   and   E   are on the line k   through   C   parallel to and further that   A   and   D are on opposite sides of   while   B   and   E   are on opposite sides of . Under this setup, we need to prove that and are opposite rays, so that we can apply Proposition 34 of Chapter 1 [about complementary angles]. We can reformulate the question about opposite rays as being about whether   D - C   and   E - C   are negative scalar multiples of each other. Since we're given that   k   is parallel to   ,   it is possible to compare either   D - C   or   E - C   with   B - A,   determining in each case whether the vector in question is a scalar multiple of   B - A,   with a positive coefficient or with a negative coefficient.

    Now, the text says that the only other loose end is about showing that   A   and   B are on the same side of   k.   Actually, in the application of Proposition 33 of Chapter 1 [about addition of angular measure], one needs to check that   B   is in the interior of angle   ACD.   Showing that   A   and   B are on the same side of   k   is part of this. But it also involves showing that   B   and   D are on the same side of   .   What was proved about oppositeness of rays in the other part of the problem can be very helpful here.
     


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